The method only works on the visible tab in each window, rather than
for all tabs. The ID argument is window, rather than tab. Try:
(untested, and will need window permission as well as tab permission)
chrome.windows.getAll(null, function(windows) {
for (var i = 0; i < windows.length; i++) {
chrome.tabs.captureVisibleTab(windows[i].id,
function(dataUrl) {
document.getElementById('body').innerHTML +=
'<img src="'+dataUrl
+'" />';
});
}
});
chrome.windows.getAll(object getInfo, function callback)
On Sat, Dec 12, 2009 at 10:22 PM, Tom <tom.extensi...@googlemail.com> wrote:
> This is the code snippet
>
> chrome.tabs.getAllInWindow(null, function(tabs) {
> for (var i = 0; i < tabs.length; i++) {
> chrome.tabs.captureVisibleTab(tabs[i].id,
> function(dataUrl) {
> document.getElementById('body').innerHTML += '<img
> src="'+dataUrl
> +'" />';
> });
> }
> });
>
> then in the body section there is a div tag like this
>
> <div id="body"></div>
>
> And its not capturing flash content.
>
> Tom
>
> On Dec 12, 9:41 pm, Mohamed Mansour <m...@chromium.org> wrote:
>> Can you show a code snippet on what your are doing? Maybe the screenshot you
>> are having is flash content (which it doesn't currently support)? Maybe the
>> tab is invalid.
>>
>> -Mohamed Mansour
>>
>>
>>
>> On Sat, Dec 12, 2009 at 4:20 PM, Tom <tom.extensi...@googlemail.com> wrote:
>> > Thanks Mohamed,
>>
>> > It all seems to be working, how ever the images are appearing blank.
>> > They are 1440x780 and in inspector there are no errors reported. Even
>> > when capturing the current window the images appear blank.
>>
>> > Tom
>>
>> > On Dec 12, 8:52 pm, Mohamed Mansour <m...@chromium.org> wrote:
>> > > Hi Tom,
>>
>> > > You are placing the wrong thing in the source attribute:
>> >http://code.google.com/chrome/extensions/tabs.html#method-captureVisi...
>>
>> > > <http://code.google.com/chrome/extensions/tabs.html#method-captureVisi..
>> > .>The
>> > > callback function for captureVisibleTab has this defined as:
>> > > "function(string dataUrl) {...})"
>>
>> > > You would use the "dataUrl" to assign the 'src' property of an HTML
>> > Image
>> > > element for display.
>>
>> > > An example being:
>>
>> > > <script>
>> > > chrome.tabs.captureVisibleTab(null, function(dataUrl) {
>> > > content = document.getElementById('screenshots');
>> > > var image = document.createElement('img');
>> > > image.setAttribute('src', dataUrl);
>> > > content.appendChild(image);});
>>
>> > > </script>
>>
>> > > <span id="screenshots"></span>
>>
>> > > -Mohamed Mansour
>>
>> > > On Sat, Dec 12, 2009 at 11:55 AM, Tom <tom.extensi...@googlemail.com>
>> > wrote:
>> > > > Is it supposed to be used like this?
>>
>> > > > var visualTab = chrome.tabs.captureVisibleTab(20, function(capture)
>> > > > {}););
>> > > > document.getElementById('content').innerHTML += '<img src="'+visualTab
>> > > > +'" />';
>>
>> > > > Thats what I'm doing at the moment and I can't get it to work. (I'm
>> > > > sure 20 is a valid tab id)
>>
>> > > > Please could someone tell me what I'm doing wrong.
>>
>> > > > Thanks
>>
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