On Sat, Dec 12, 2009 at 6:02 PM, Daniel Wagner-Hall <dawag...@gmail.com>wrote:
> The method only works on the visible tab in each window, rather than
> for all tabs. The ID argument is window, rather than tab. Try:
> (untested, and will need window permission as well as tab permission)
>
Actually, you only need the "tabs" permission, the window and tabs modules
interact so closely so they share just one permission between them which is
"tabs".
Tom, as Daniel stated, you cannot capture non visible tabs, you can just
capture the visible area of the currently selected tab in the window you
specified.
-Mohamed Mansour
> chrome.windows.getAll(null, function(windows) {
> for (var i = 0; i < windows.length; i++) {
> chrome.tabs.captureVisibleTab(windows[i].id,
> function(dataUrl) {
> document.getElementById('body').innerHTML +=
> '<img src="'+dataUrl
> +'" />';
> });
> }
> });
>
> chrome.windows.getAll(object getInfo, function callback)
>
> On Sat, Dec 12, 2009 at 10:22 PM, Tom <tom.extensi...@googlemail.com>
> wrote:
> > This is the code snippet
> >
> > chrome.tabs.getAllInWindow(null, function(tabs) {
> > for (var i = 0; i < tabs.length; i++) {
> > chrome.tabs.captureVisibleTab(tabs[i].id,
> function(dataUrl) {
> > document.getElementById('body').innerHTML += '<img
> src="'+dataUrl
> > +'" />';
> > });
> > }
> > });
> >
> > then in the body section there is a div tag like this
> >
> > <div id="body"></div>
> >
> > And its not capturing flash content.
> >
> > Tom
> >
> > On Dec 12, 9:41 pm, Mohamed Mansour <m...@chromium.org> wrote:
> >> Can you show a code snippet on what your are doing? Maybe the screenshot
> you
> >> are having is flash content (which it doesn't currently support)? Maybe
> the
> >> tab is invalid.
> >>
> >> -Mohamed Mansour
> >>
> >>
> >>
> >> On Sat, Dec 12, 2009 at 4:20 PM, Tom <tom.extensi...@googlemail.com>
> wrote:
> >> > Thanks Mohamed,
> >>
> >> > It all seems to be working, how ever the images are appearing blank.
> >> > They are 1440x780 and in inspector there are no errors reported. Even
> >> > when capturing the current window the images appear blank.
> >>
> >> > Tom
> >>
> >> > On Dec 12, 8:52 pm, Mohamed Mansour <m...@chromium.org> wrote:
> >> > > Hi Tom,
> >>
> >> > > You are placing the wrong thing in the source attribute:
> >> >http://code.google.com/chrome/extensions/tabs.html#method-captureVisi.
> ..
> >>
> >> > > <
> http://code.google.com/chrome/extensions/tabs.html#method-captureVisi..
> >> > .>The
> >> > > callback function for captureVisibleTab has this defined as:
> >> > > "function(string dataUrl) {...})"
> >>
> >> > > You would use the "dataUrl" to assign the 'src' property of an HTML
> >> > Image
> >> > > element for display.
> >>
> >> > > An example being:
> >>
> >> > > <script>
> >> > > chrome.tabs.captureVisibleTab(null, function(dataUrl) {
> >> > > content = document.getElementById('screenshots');
> >> > > var image = document.createElement('img');
> >> > > image.setAttribute('src', dataUrl);
> >> > > content.appendChild(image);});
> >>
> >> > > </script>
> >>
> >> > > <span id="screenshots"></span>
> >>
> >> > > -Mohamed Mansour
> >>
> >> > > On Sat, Dec 12, 2009 at 11:55 AM, Tom <
> tom.extensi...@googlemail.com>
> >> > wrote:
> >> > > > Is it supposed to be used like this?
> >>
> >> > > > var visualTab = chrome.tabs.captureVisibleTab(20,
> function(capture)
> >> > > > {}););
> >> > > > document.getElementById('content').innerHTML += '<img
> src="'+visualTab
> >> > > > +'" />';
> >>
> >> > > > Thats what I'm doing at the moment and I can't get it to work.
> (I'm
> >> > > > sure 20 is a valid tab id)
> >>
> >> > > > Please could someone tell me what I'm doing wrong.
> >>
> >> > > > Thanks
> >>
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