The numbers you have might work, but they definately aren't the best to use.
I have a couple of comments inline below -
>I have four different interfaces on a 2514 router (e0,e1,s0,s1), each
>interface is on a different subnet, and the mask is 30 bits. Here's they
>are:
>int e0 = 172.16.10.4 /30
>int e1 = 172.16.10.8 /30
>int s0 = 172.16.10.12 /30
>int s1 = 172.16.10.16 /30
>( I only want two addresses per subnet)
Those are good subnets for two devices per subnet, but not to be put on
the interface. The .4, .8, .12, and .16 are the 'net' addresses for those
subnets. You would want to put .5, .9, .13, .16 on the actually interface.
with .6, .10, .14, and .17 being the remote devices and .7, .11, .15, and
.18 as the broadcast address for those nets.
I wasn't too sure from your letter if you were pointing out the subnets
that would be placed on each interface, or the actuall IP address.
>I'm running OSPF routing protocol on this router. Each route is
>configured in a different area, so that makes this router an Area Border
>Router.
>here's the logic:
>router ospf 23
>route 172.16.10.4 0.0.0.0 area 1
>route 172.16.10.8 0.0.0.0 area 2
>route 172.16.10.12 0.0.0.0 area 3
>route 172.16.10.16 0.0.0.0 area 4
>
>
>I want to summarize the addresses into one route for the routing table.
>Is this possible?
>Here's the binaries on the last octet:
>4 = .00000100
>8 = .00001000
>12= .00001100
>16= .00010000
>I came up with summary-address 172.16.10.0 255.255.255.224
>(ABR script = area 23 range 172.16.10.0 255.255.255.224)
>Is this correct?
Well, 172.16.10.0/27 will give you a netmask of .000/01010
That wil summarize all networks from .0 to .31 - so, it will cover the range
you need. But you will have to make sure not to use the .20 through .31
anywhere else in the network.
This one can't be summarized in one summary-address if you want to keep it
to these networks exactly. You would have to use 172.16.10.4/28 which would
cover .0 through .15 and then the 172.16.10.0/30 for that range.
Hope that helps
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