You've got (the last) three bits on the third octet to play with, which
leaves you with 2^3 = 8 cont. numbers (the first one being 168) : 168,
169,..., 175.
You may also think of the /21 as 2 /22s, so 4 /23s, so 8 /24s.
mh
>hey im just learning about vlsm, so theres a good chance >this is wrong :)
>anyways i'd say
>172.108.168.0
>x.x.169.0
>x.x.170.0
>x.x.171.0
>x.x.172.0
>x.x.173.0
>x.x.174.0
>x.x.175.0
>
>Justin...
>
>
>>On Thu, 15 Jun 2000, jeongwoo park wrote:
>>
>> I have a guestion regarding VLSM
>> How many subnet addresses can be summarized by
>>172.108.168.0/21?
>> how could you calculate it?
>> thanks in advance.
>>
>> ........................................................
>> iWon.com http://www.iwon.com why wouldn't you?
>> ........................................................
>>
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