Hey, gang,
That was a good one! It's been a year since I took my last CCNP exam, but
I do believe that I improved my score by watching the wording. Host address
vs. network address vs. subnet address mixed with classless or classful, add
a pinch of subnet zero, and oh, wait, let's use DLSW+!!! Well, needless to
say, I know some engineers that are brilliant in the real world, but missed
points due to their overquick reading of a question.
Raymond, thank you for including me the group that you did...I am highly
complimented!
By the way, I am moving from Germany to Texas in a few weeks. My new
contributing address will still appear as "Cthulu, CCIE Candidate", but will
be homed on [EMAIL PROTECTED] ( I don't know why, but the works
of H.P. Lovecraft seem appropriate literature for studying Cisco...is that
just me?)
Take care,
Charles
-----Original Message-----
From: Raymond Everson (Rainman) [mailto:[EMAIL PROTECTED]]
Sent: Monday, June 26, 2000 10:20 PM
To: Michael L. Williams; Daniel Ma; Cthulu, CCIE Candidate;
[EMAIL PROTECTED]; Bal Sandhu; Sanjay.Padmanabhan; Chuck Larrieu;
Lou Nelson; Aaron K. Dixon; [EMAIL PROTECTED]; Oz; study group
Subject: Re: Sample Question Question
Hi Michael, Daniel, Charles, Duarte, Bal, Sanjay, Chuck, Lou, Aaron, Sam,
Oz...
I've learned two things from this (seriies of) question(s).
#1: People would MUCH rather talk about meat/potatoes of tech
questions
than some of the off-subject crap that gets thrown into this
discussion
group; and
#2: There are some genuinely nice and interested people out there.
This question raises the paradox which we face when taking the CCIE written,
and then evaluating how to handle a lab scenario: I don't have enough
information
to answer completely. Please let me explain....
Everyone agrees that the answer is "e. none of the above". Review the
provided
answer all the way at the bottom. Under normal circumstances (with no
consideration for zero subnet-enable) .... the statement is correct, this
would
be
an illegal address/mask pair. But, considering the possibilites of the
world,
I don't see a thing wrong with 193.243.12.43/25. ... and I would have been
totally messed up by that statement.
... which is why Sanjay and Michael and, of course Chuck are getting close
to
being ready for the lab..... attention to detail.... the "Spot the Issue"
gotcha
in
the config with this scenario is a single line of code: zero subnet-enable
btw: Chuck Larrieu wins hands down for his completely awesome explanation
of
how to figure out what evens have in common, and what odds have in common.
After that, it's a simple matter of understanding inverse masking.... DOH!
Thanks a million, you're a fine bunch.
Rainman
"Michael L. Williams" wrote:
> I hope I'm right =)
>
> I would say the answer is E. Here's why.
>
> 193.x.y.z is a Class C address. So the first three octects of the subnet
> mask are the "network" portion, and the last octect is the "hosts"
portion.
>
> What they have done here by making the last octect 128 (1000 0000),
instead
> of 0 (0000 0000), is to split that 256 hosts into two subnets, by taking
> that first bit away from the "hosts" and using it for "network". Each
subnet
> now has up to 128 hosts (of course you have to subtract 2; 1 for the
network
> and 1 for broadcast, so each subnet technically can only have up to 126
> hosts).
>
> So, the valid host addressess in the two subnets would be 193.243.12.1 -
> 193.243.12.126 (193.243.12.0 is the network address, and 193.243.12.127 is
> the broadcast for the 1st subnet), and 193.243.12.129 - 193.243.12.254
> (where 193.243.12.128 is the network address for subnet 2, and
> 193.243.12.255 is the broadcast address for subnet 2)
>
> So, is they ask us the "network address" for the IP address 193.243.12.43
> with a subnet mask of 255.255.255.128, the answer is 193.243.12.0. If
there
> were to ask the "network address" for 193.243.12.181 with a subnet mask of
> 255.255.255.128, the answer is 193.243.12.128.
>
> Hope this helps some........
>
> Mike W.
>
> ----- Original Message -----
> From: "Raymond Everson (Rainman)" <[EMAIL PROTECTED]>
> Newsgroups: groupstudy.cisco
> Sent: Saturday, June 24, 2000 6:10 PM
> Subject: Sample Question Question
>
> > I ran across this question some time ago and kept the darned thing
> > because (I *guess*) I still have something to learn about IP ... . just
> > when I was *sure* I had it down cold. Could you lend a fella a hand?
> >
> > Given the IP address of 193.243.12.43 and a subnet mask of
> > 255.255.255.128, what is the subnet address?
> >
> > a.194.243.12.32
> > b.193.243.0.0
> > c.194.243.12.43
> > d.193.243.12.128
> > e.None of the above.
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > .
> > e. None of the above
> >
> > The Subnet Address is found by setting all of the host bits in an
> > address to 0.
> > According to the mask, there are 7 host bits, so applying this rule
> > yields a subnet
> > address of 193.243.12.0. However, closer inspection yields that there is
> > only one
> > subnet bit in this Class C address - therefore, this is an illegal
> > address/mask pair.
> >
> > ___________________________________
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