None of the above.
With classful IP, it's an invalid subnet mask. The .128 indicates a subnet
mask of only one bit, giving you only two subnets (193.243.12.0, and
193.243.12.128). You always lose two subnets when using a subnet mask with
classful IP : the first .0 subnet would conflict with the address of the
network, (is 193.243.12.0 referring to the network or the subnet?), and the
.128 subnet would give a subnet address of all 1s (with only one bit,
there's just one 1), resulting in a broadcast, so it's also invalid.
Now, with classless IP, the answer is still (e) None of the above. It's a
valid IP and subnet mask, as long you've given the ip subnet zero command.
The subnet address would be 193.243.12.0 (which wasn't listed as an answer).
Broadcast for the subnet would be .127, leaving you the .1 - 126. for hosts.
My two bits,
----- Original Message -----
From: Raymond Everson (Rainman) <[EMAIL PROTECTED]>
To: study group <[EMAIL PROTECTED]>
Sent: Wednesday, June 21, 2000 12:01
Subject: Sample Question Question
> I ran across this question some time ago and kept the darned thing
> because (I *guess*) I still have something to learn about IP ... . just
> when I was *sure* I had it down cold. Could you lend a fella a hand?
>
> Given the IP address of 193.243.12.43 and a subnet mask of
> 255.255.255.128, what is the subnet address?
>
> a.194.243.12.32
> b.193.243.0.0
> c.194.243.12.43
> d.193.243.12.128
> e.None of the above.
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
> .
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> e. None of the above
>
> The Subnet Address is found by setting all of the host bits in an
> address to 0.
> According to the mask, there are 7 host bits, so applying this rule
> yields a subnet
> address of 193.243.12.0. However, closer inspection yields that there is
> only one
> subnet bit in this Class C address - therefore, this is an illegal
> address/mask pair.
>
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