Let me try a quick stab at it:
Let's say you have the following token ring mac address:
0110.1234.5678
Convert the address to binary:
0 1 1 0 1 2 3 4 5
6 7 8
0000 0001 0001 0000 0001 0010 0011 0100 0101 0110 0111 1000
Swap the bytes - 0000 0001 now equals 0001 0000 etc....
1 0 0 1 2 1 4 3 6
5 8 7
0001 0000 0000 0001 0010 0001 0100 0011 0110 0101 1000 0111
You should now see that the positions have been swapped; 0 and 1, 1 and 0
etc?
Now swap the bits: e.g. 0001 is reversed to equal 1000
8 0 0 8 4 8 2 C 6
A 1 E
1000 0000 0000 1000 0100 1000 0010 1100 0110 1010 0001 1110
So now you should see that 0110.1234.5678 (non-canonical) is equal to
8008.482C.6A1E (canonical).
Remember that a mac address is 48 bits long or 6 bytes. Take each byte
separately and convert to binary. Swap the byte position(s) and reverse the
bits
in each byte.
Hope this helps..dj
"Mike Neal" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Can anyone help me with Bit swapping from Token to Ethernet.
> I can't seem to grasp how it is done.
>
> Thanks,
> Mike
>
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