Correct. You need 14 subnets, a block of 16. Therefore your third octet will
be 176-191.
"Hunt Lee" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Can anyone please explain to me how to derive the answer of this
> question?
>
> A company has been assigned a subnet of 172.16.176.0/20, and wants the
> next four available bits to create 14 subents, each containing an equal
> number of hosts. Which of the following could represent one of these
> subnets?
>
> A) 172.16.255.0/24
> B) 172.16.193.0/24
> C) 172.16.183.0/24
> D) 172.16.16.0/24
> E) 172.16.0.0/24
> F) 172.16.190.0/24
>
> Answer is C and F
>
>
> Regards,
> Hunt Lee
> IP Solution Analyst
> Cable and Wireless (Sydney)
>
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