At 02:17 PM 6/7/01, Aleksey Loginov wrote:
>Hi!
>Question about rule 5-4-3.
>How it's work for 10BaseT?
>This scheme correct?
>
>         hosts              hosts              hosts
>          \|/                \|/                \|/
>host --- hub --- repeat --- hub --- repeat --- hub --- host
>          /|\                /|\                /|\
>         hosts              hosts              hosts
>

Great job on the ASCII art! It's quite pleasing to the eye. ;-)

A 10BaseT hub is a repeater. Dare I say that there's no difference between 
a Layer-1 repeater and a hub? Just like there's no difference between a 
Layer-2 switch and a bridge, or a Layer-3 switch and a router. Argh.

One topology that became popular for explaining propagation delay on an 
Ethernet network was the 5-4-3 topology. With a 5-4-3 topology, you can 
have up to five segments in series, with up to four repeaters, and no more 
than three mixing segments. If three mixing segments are used, then the 
remaining two segments must be link segments. A mixing segment is one that 
can have more than one attachment, such as a coax cable. A link segment is 
a point-to-point link. It could be a fiber link between hubs, for example. 
A 10BaseT hub connection to an end station is also a link segment.

The 5-4-3 topology is just one of many models that work actually. It is a 
simplification of the actual rule that says that the round-trip propagation 
delay in one collision domain must not exceed the time it takes a sender to 
transmit 512 bits, which is 51.2 5s for 10-Mbps Ethernet, and is also known 
as the slot time.

A single collision domain must be limited in size so that a station sending 
a minimum-sized frame (64 bytes or 512 bits) can detect a collision and jam 
signal reflecting back from the opposite side of the network, while the 
station is still sending the frame. Otherwise, the station would be 
finished sending and not listening for a collision, thus losing the 
efficiency of Ethernet to detect a collision and quickly retransmit the 
frame. For a higher layer to notice that the frame needs retransmitting 
takes much more time. Ethernet retransmissions occur within nanoseconds.

Priscilla


>Any comments, please.
>
>Best regards,
>Aleksey
________________________

Priscilla Oppenheimer
http://www.priscilla.com




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