Hi, 

I am not to sure myself here. I will ask one of my colleagues here as well
to see if he has any light that he can shed here.

Regards

Andrew

-----Original Message-----
From: Diffy De Villiers [mailto:[EMAIL PROTECTED]]
Sent: 14 January 2002 13:01 PM
To: [EMAIL PROTECTED]
Subject: URGENT - PLEASE HELP - OSPF summary route cost. [7:31832]


Hi Everybody

This is the third time that I am posting this message to this
studygroup,
I had no reply to the previous two postings. Hopefully someone will be
able to assist me this time. 

I have a problem understanding how costs are calculated for OSPF
summary
routes. To understand my problem refer to the following example:


This is the internetwork diagram (with 4 routers A,B,C & D):

      netw 1       netw 2       netw 3        netw 4
[ A ]--------[ B ]--------[ C ]---------[ D ]---------|
      cost 1       cost 4       cost 64       cost 16

----------------------------------
Here are my router configurations:
----------------------------------
hostname RouterA
!
interface Serial0
 description connected to RouterB via network 1
 ip address 192.168.1.2 255.255.255.0
 ip ospf cost 1
 no fair-queue
!
router ospf 10
 network 192.168.1.0 0.0.0.255 area 1
--------------------------------------
hostname RouterB
!
interface Ethernet0
 description connected to RouterC via network 2
 ip address 192.168.2.1 255.255.255.0
 ip ospf cost 4
!
interface Serial0
 description connected to RouterA via network 1
 ip address 192.168.1.1 255.255.255.0
 ip ospf cost 1
!         
router ospf 10
 network 192.168.1.0 0.0.0.255 area 1
 network 192.168.2.0 0.0.0.255 area 0
--------------------------------------
hostname RouterC
!
interface Ethernet0
 description connected to RouterB via network 2
 ip address 192.168.2.2 255.255.255.0
 ip ospf cost 4
!
interface Serial0
 description connected to RouterD via network 3
 ip address 192.168.3.1 255.255.255.0
 ip ospf cost 64
!
router ospf 10
 network 192.168.2.0 0.0.0.255 area 0
 network 192.168.3.0 0.0.0.255 area 2
--------------------------------------
hostname RouterD
!
interface Ethernet0
 description network 4
 ip address 192.168.4.1 255.255.255.0
 ip ospf cost 16
!
interface Serial0
 description connected to RouterC via network 3
 ip address 192.168.3.2 255.255.255.0
 ip ospf cost 64
 no fair-queue
!
router ospf 10
 network 192.168.3.0 0.0.0.255 area 2
 network 192.168.4.0 0.0.0.255 area 2
--------------------------------------

If we do a "show ip route" at routerA we get the following output:

RouterA>show ip route
Codes: C - connected, S - static, I - IGRP, R - RIP, M - mobile, B -
BGP
       D - EIGRP, EX - EIGRP external, O - OSPF, IA - OSPF inter area 
       N1 - OSPF NSSA external type 1, N2 - OSPF NSSA external type 2
       E1 - OSPF external type 1, E2 - OSPF external type 2, E - EGP
       i - IS-IS, L1 - IS-IS level-1, L2 - IS-IS level-2, * -
candidate
default
       U - per-user static route, o - ODR

Gateway of last resort is not set

C    192.168.1.0/24 is directly connected, Serial0
O IA 192.168.2.0/24 [110/5] via 192.168.1.1, 00:23:26, Serial0
O IA 192.168.3.0/24 [110/133] via 192.168.1.1, 00:18:51, Serial0
O IA 192.168.4.0/24 [110/85] via 192.168.1.1, 00:18:56, Serial0


Now for my problem:

Looking at the diagram above, the metric from Router A to network 4 is
85.
This is perfectly understandable (sumtotal of all the costs: 85 =
1+4+64+16).

BUT NOW: The metric from RouterA to network 3 is 133!!! This is higher
than the metric to network 4 even though we access network 4 via
network
3.
Logically I would have thought the cost to network 3 has to be 69
(64+4+1), not 133. Where does the cost-difference of 64 come from? The
only rational explanation I have for this is that the ABR for area 2
added it, but why??? And why only add this cost factor for network 3
(and not for network 4)???

Please assist me if you know the answers since I cannot figure out a 
reasonable explanation.

Thank you for your support.

Abraham de Villiers




Message Posted at:
http://www.groupstudy.com/form/read.php?f=7&i=31834&t=31832
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