Hi, all:
I'm tring to solve such a problem: Given a string consisting of "1" and
"0", find all the locations of "1", and print them in the format of
intervals.
For example: "00101110101110" => 3, 5-7, 9, 11-13
Here is my solution:
(defn bar [x]
(letfn [(foo [mystr]
(->>
(map-indexed vector mystr)
(filter #(= (second %) \1))
(map (comp inc first))
(partition-all 2 1)
(filter #(= 2 (count %)))))]
(let [y (map #(if (> (- (second %) (first %)) 1) (print (first %) ", "
(second %) "-")) (foo x))]
(print (ffirst y) "-" y (last (last (foo x)))))))
With the code above, I got many nils in the result:
(bar "00101110101110") => 3 , 5 -nil - (nil nil 7 , 9 -nil 9 , 11 -nil nil
nil nil) 13
How can I remove them?
And, is there any way to make my code more concise?
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