This is a little more concise:
(->> "00101110101110"
(map-indexed vector)
(partition-by second)
(filter #(= (second (first %)) \1))
(map (comp (fn [[f & tail]]
(if rest (str f "-" (last tail)) (str f)))
(partial map first))))
On Mon, Dec 22, 2014 at 8:09 PM, Pauli <pauli.mat...@gmail.com> wrote:
> Hi, all:
>
> I'm tring to solve such a problem: Given a string consisting of "1" and
> "0", find all the locations of "1", and print them in the format of
> intervals.
>
> For example: "00101110101110" => 3, 5-7, 9, 11-13
>
> Here is my solution:
>
> (defn bar [x]
> (letfn [(foo [mystr]
> (->>
> (map-indexed vector mystr)
> (filter #(= (second %) \1))
> (map (comp inc first))
> (partition-all 2 1)
> (filter #(= 2 (count %)))))]
> (let [y (map #(if (> (- (second %) (first %)) 1) (print (first %) ", "
> (second %) "-")) (foo x))]
> (print (ffirst y) "-" y (last (last (foo x)))))))
>
>
> With the code above, I got many nils in the result:
>
> (bar "00101110101110") => 3 , 5 -nil - (nil nil 7 , 9 -nil 9 , 11 -nil
> nil nil nil) 13
>
> How can I remove them?
>
> And, is there any way to make my code more concise?
>
>
>
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