whoops...

       (defn in-step [xs]
         (let [[x1 x2] xs]
           (= (- x2 x1) 1)))

On Monday, December 22, 2014 11:38:49 PM UTC-8, Tim wrote:
>
> Another option (though Bens does look nicer!) 
>
> (loop [xs (->> "00101110101110"
>             (map vector (iterate inc 1))
>             (filter #(= (last %) \1))
>             (map first))
>       it nil]
>   (let [steps (partition 2 1 xs)
>         [i o] (split-with in-step steps)]
>     (cond (every? empty? steps)
>             (str it (first xs))
>           (empty? i)
>             (recur (rest xs)(str it (first xs) ","))
>    :else (recur (last (split-at (count i) xs)) (str it (ffirst i) "-")))))
>
>
>>

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