Dennis

I think is the cos of true wind angle, not apparrent


On Fri, Oct 11, 2013 at 9:19 PM, Dennis C. <capt...@yahoo.com> wrote:

> Eric,
>
> For simplicity, think of wind relative VMG as the boatspeed through the
> water multiplied by the cosine of the apparent wind angle.
>
> If you're sailing at 40 degrees to the wind at 6 knots, the wind relative
> VMG is 6 * 0.766 or 4.6 knots.  That is, you're making 4 knots dead upwind.
>
> In the extreme, if you were motoring dead upwind at 6, the VMG would be 6
> * cosine (0) or 6 * 1 = 6 knots.  If you were sailing at 90 degrees to the
> wind, it would be 6 * cosine (90) or 6 * 0 = 0.
>
> The calculation is independent of GPS input.
>
> Hope this helps.
>
> Dennis C.
> Touche' 35-1 #83
> Mandeville, LA
>
>
>
>   On Friday, October 11, 2013 5:22 PM, Eric Frank <efran...@mac.com>
> wrote:
>
> How is VMG upwind calculated? Earlier on this list, someone made the good
> point that VMG calculated to a waypoint (from GPS data) is not the best
> way, and my exploration of Google hits confirm that.  One should focus on
> VMG upwind.  But I am struggling to figure out how that is calculated.  To
> get true wind direction, the wind devices I am familiar with require input
> from GPS data, (usually RMC, which includes SOG and COG).  But they don't
> require knowledge of the orientation of the boat, i.e. HDG (on my boat,
> from the fluxgate compass connected to the Raymarine autopilot).  If the
> boat were really going in the direction it is pointed, then HDG would be
> the same as COG, so the calculation of VMG upwind would be straightforward.
>  But if the boat is not moving exactly in that direction (current, or
> (importantly) leeway because of heeling when going upwind), I don't
> understand how sufficient information is being sent to the wind device to
> make the calculation.  Wouldn't it be required to know the actual compass
> heading of the boat, so that could be compared to the COG?  Do higher-end
> wind devices also require input from the compass (which is not always
> exactly right in my experience). Google-searching so far has not provided
> an explanation, and my high school trig is so far in the past that I can't
> figure this out.
>
> Input welcome.
>
> Eric Frank
> Cat's Paw
> C&C 35 Mk II
> Mattapoisett, MA
>
>
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