That's going to create a new copy of the array every time the block is executed, and the array is not accessible outside of the scope of the block. Matt was asking about:
__block char array1[5];
NSBlockOperation * foo = [NSBlockOperation blockOperationWithBlock:^{
array1[0] = 'T';
}
Dave
On Jun 26, 2010, at 8:48 PM, Tony Romano wrote:
> hmmm. Your saying this doesn't work?
>
> NSBlockOperation * foo = [NSBlockOperation
> blockOperationWithBlock:^{
> __block char array1[5];
>
> array1[0] = 'T';
> }];
>
>
> It works fine for me. Are you saying something different?
>
> -Tony
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