I understand all that. I was providing an example to seek clarity in his
question. But I understand what he is asking now, thanks.
-Tony
On Jun 26, 2010, at 7:50 PM, Dave DeLong wrote:
> That's going to create a new copy of the array every time the block is
> executed, and the array is not accessible outside of the scope of the block.
> Matt was asking about:
>
> __block char array1[5];
> NSBlockOperation * foo = [NSBlockOperation blockOperationWithBlock:^{
> array1[0] = 'T';
> }
>
> Dave
>
> On Jun 26, 2010, at 8:48 PM, Tony Romano wrote:
>
>> hmmm. Your saying this doesn't work?
>>
>> NSBlockOperation * foo = [NSBlockOperation
>> blockOperationWithBlock:^{
>> __block char array1[5];
>>
>> array1[0] = 'T';
>> }];
>>
>>
>> It works fine for me. Are you saying something different?
>>
>> -Tony
-Tony
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