Ok. That makes sense. Sent from my iPhone
On Jan 2, 2011, at 9:26 PM, Phil Steitz <phil.ste...@gmail.com> wrote: > On Sun, Jan 2, 2011 at 11:46 PM, Ted Dunning <ted.dunn...@gmail.com> wrote: > >> On Sun, Jan 2, 2011 at 2:05 PM, Phil Steitz <phil.ste...@gmail.com> wrote: >> >>> We don't precisely define what we mean by the support of a distribution >>> anywhere. I have been assuming that we mean the smallest closed set such >>> that its complement has probability 0. >> >> >> Why closed? >> >> Why not just the smallest set such that the complement has probability 0? >> > > Because that in general will not be well-defined. Consider, for example, > the support of the Beta distribution. The smallest closed set whose > complement has probability 0 is [0, 1] (independently of the parameters). > If the definition does not require that the set be closed, then when you > consider (0, 1], [0, 1), [0, 1] - {x} for any x in [0,1], or [0, 1] minus > any finite number of points...you see that there will be no unique smallest > (in terms of inclusion) set whose complement has probability 0. > > Phil --------------------------------------------------------------------- To unsubscribe, e-mail: dev-unsubscr...@commons.apache.org For additional commands, e-mail: dev-h...@commons.apache.org