> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Eli >Marmor > Sent: 12 March 2002 12:39
> Sander Striker wrote: >> Consider: >> >> lines += 1; >> >> Which is the same as: >> >> lines++; >> >> Personally I am slowed down when I see this: >> >> ++lines; >> >> Because I am used to seeing the op _after_ the variable. > > "lines++" is NOT the replacement of "lines += 1", but of "(lines+=1)-1" Uhuh, true. If you are going to use the statement inside an expression. If you are not, and it is just a one-liner, as above, the meaning is the same. > Only "++lines" is the replacement of "lines += 1". > > For example, if you have to increment "lines" and after that insert 2 > times of it into result, and you MUST do it in one instruction, then > "result = 2 * (lines += 1)" can't be replaced by "result = 2 * lines++" > but only by "result = 2 * ++lines". It's not styling; It's a totally > different thing. I am not going to be amused if I see something like your example being used anywhere ;) > What you are USED to see, is your own taste, but in this case, even the > meaning is different. You are missing my point. > But again, the whole issue is minor... Yeah, let's close this thread on that account. Sander
