On 22/10/2007, Jim Jagielski <[EMAIL PROTECTED]> wrote: > Say you are looking for 'foo' and have a bucket that > contains 'jimfoojag'. The fast way to handle this would > be to split off 3 buckets from this, one containing > 'jim', the other containing 'jag' and the middle one that > contains the substitute for 'foo' (say it's 'bar'). The rub > is that the pattern matching looks at buckets only, so you > wouldn't see a full bucket that contains 'jimbarjag' and > so if you had a search for 'mbarj', it would be missed using > the "fast way". In the slow way (flattening), instead > of creating the 3 buckets, you go ahead and smash them all > together resulting in the single bucket that now contains > 'jimbarjag'. Now the search for 'mbarj' would succeed.
That's much clearer now, thanks. I've committed my first shot, so please give it a critical eye. Is there a need to add further explaination of 'f' here? Also, surely there's a less contrived example than s/foo/bar/.. -- noodl
