On 30 Aug, Don Lewis wrote:
> On 30 Aug, Kay Schenk wrote:
>>
>>
>> On 08/29/2016 04:14 PM, Don Lewis wrote:
>>> A couple -Wtautological-undefined-compare warnings:
>>>
>>> warning: reference cannot be bound to dereferenced null pointer in
>>> well-defined C++ code; comparison may be assumed to always evaluate to
>>> false [-Wtautologica
>>> l-undefined-compare]
>>> if (&other == NULL) {
>>> ^~~~~ ~~~~
>>
>> This one is apparently an old holdoever from C and not recommended
>> currently...
>>
>> See. e.g:
>> http://stackoverflow.com/questions/17772103/can-i-use-if-pointer-instead-of-if-pointer-null
>>
>> It probably needs an update to accomplish what it's trying to do.
>>
>>
>>>
>>> warning: 'this' pointer cannot be null in well-defined C++ code; comparison
>>> may be assumed to always evaluate to false [-Wtautological-undefin
>>> ed-compare]
>>> if(this == 0 || this == &src) {
>>> ^~~~ ~
>>>
>>
>> Same here...
>
> nullptr is a c++11 thing and is not supported by older compilers.
>
> When I upgraded one of the bundled packages (nss?) I found it had some
> test code that used nullptr that didn't compille on many of our
> platforms. I had to disconnect the tests from the build.
>
> The warnings are about things that can't be null. In the first case if
> you have a reference to another variable, then the address of that
> variable can't be null. In the second case, this could only be null if
> you call a method on a null object.
>
> One of the bits of code that I looked at for the first error looked
> suspicious. It looks like it is passing *ptr as a reference parameter.
> I'm not sure that's legal, and then the question is what happens if ptr
> is null? Other calls to the same function were passing a regular
> variable by reference. The appropriate fix in this case my be to create
> a variant function that accepts a pointer and checks for NULL. Rather
> than checking &ref == NULL.
Hmn, this is what I was afraid of. The following code compiles without
any warnings or errors:
#include <stdio.h>
void
func(int &arg)
{
fprintf(stderr, "%p\n", &arg);
}
int
main(void)
{
int i, *p1, *p2;
i = 42;
p1 = &i;
p2 = NULL;
func(*p1);
func(*p2);
}
Running it gives the following output:
0x7fffffffea7c
0x0
So basically it is allowing *p2 to be dereferenced even though it is
NULL, and the address of the reference variable inside func() is 0.
I guess this isn't well defined C++ code ...
<http://stackoverflow.com/questions/28689269/how-to-fix-reference-cannot-be-bound-to-dereferenced-null-pointer-warning>
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