Ok, at present there is only one SimpleModule, the default. I can make it v2 or v3 but not both.

Lets say I make the SimpleModule support V2.
Then when calling IoEdgeTest for

    {"graphson-v3", true, true,
        (Function<Graph, GraphReader>) g -> g.io(IoCore.graphson()).reader().mapper(g.io(GraphSONIo.build(GraphSONVersion.V3_0)).mapper().create()).create(),         (Function<Graph, GraphWriter>) g -> g.io(IoCore.graphson()).writer().mapper(g.io(GraphSONIo.build(GraphSONVersion.V3_0)).mapper().create()).create()},

then the deserializers that run are for V2,

    static class SchemaTableIdJacksonDeserializerV2d0 extends AbstractObjectDeserializer<SchemaTable> {
        SchemaTableIdJacksonDeserializerV2d0() {
            super(SchemaTable.class);
        }

        @Override
        public SchemaTable createObject(final Map data) {
            return SchemaTable.of((String)data.get("schema"), (String) data.get("table"));
        }
    }

when createObject fires the map data has V3 elements in it like @type and @value whilst its expecting "schema" and "table"

If we make the SimpleModule support V3 then graphson-v2 will fail.

   {"graphson-v2", false, false,
       (Function<Graph, GraphReader>) g -> g.io(IoCore.graphson()).reader().mapper(g.io(GraphSONIo.build(GraphSONVersion.V2_0)).mapper().typeInfo(TypeInfo.NO_TYPES).create()).create(),        (Function<Graph, GraphWriter>) g -> g.io(IoCore.graphson()).writer().mapper(g.io(GraphSONIo.build(GraphSONVersion.V2_0)).mapper().typeInfo(TypeInfo.NO_TYPES).create()).create()},

Now the deserializers are for V3.

    static class SchemaTableJacksonDeserializerV3d0 extends StdDeserializer<SchemaTable> {
        public SchemaTableJacksonDeserializerV3d0() {
            super(RecordId.class);
        }

        @Override
        public SchemaTable deserialize(final JsonParser jsonParser, final DeserializationContext deserializationContext) throws IOException, JsonProcessingException {             final Map<String, Object> data = deserializationContext.readValue(jsonParser, Map.class);             return SchemaTable.of((String)data.get("schema"), (String) data.get("table"));
        }

        @Override
        public boolean isCachable() {
            return true;
        }
    }

This does not fire at all. Eventually I get a detached edge with an id  that is a map. It never deserialized.

So basically it only works if the SimpleModule version, i.e. serialize/deserialize code matches up with the version.

Sqlg serializes RecordId to,

    static class RecordIdJacksonSerializerV3d0 extends StdScalarSerializer<RecordId> {
        public RecordIdJacksonSerializerV3d0() {
            super(RecordId.class);
        }
        @Override
        public void serialize(final RecordId recordId, final JsonGenerator jsonGenerator, final SerializerProvider serializerProvider)
                throws IOException, JsonGenerationException {
            final Map<String, Object> m = new HashMap<>();
            m.put("schemaTable", recordId.getSchemaTable());
            m.put("id", recordId.getId());
            jsonGenerator.writeObject(m);
        }
    }

and

    static class SchemaTableJacksonSerializerV3d0 extends StdScalarSerializer<SchemaTable> {
        SchemaTableJacksonSerializerV3d0() {
            super(SchemaTable.class);
        }

        @Override
        public void serialize(final SchemaTable schemaTable, final JsonGenerator jsonGenerator, final SerializerProvider serializerProvider)
                throws IOException, JsonGenerationException {
            // when types are not embedded, stringify or resort to JSON primitive representations of the             // type so that non-jvm languages can better interoperate with the TinkerPop stack.
            final Map<String, Object> m = new LinkedHashMap<>();
            m.put("schema", schemaTable.getSchema());
            m.put("table", schemaTable.getTable());
            jsonGenerator.writeObject(m);
        }

    }

Hope it all makes some sense,
Pieter


On 05/09/2017 17:31, Stephen Mallette wrote:
I guess I'm trying to understand why it matters for purpose of the test. If
you mix/match versions I can't think of why the test would care one way or
the other. does sqlg serialize its id to a JSON Map?

On Tue, Sep 5, 2017 at 11:19 AM, pieter gmail <pieter.mar...@gmail.com>
wrote:

I looked at TinkerGraph's implementation. In fact I copied it. TinkerGraph
does not have any special id serialization. In fact both its
TinkerIoRegistryV3d0 andTinkerIoRegistryV2d0 registry uses TinkerModuleV2d0.


In IoCustomTest tests you call g.io(GraphSONIo.build(GraphSON
Version.V2_0)).mapper().addCustomModule(moduleV2d0).
I.e. the test manually registers the appropriate SimpleModule for each
version.

For IoEdgeTest the same needs to happen somehow. Currently I have only one
default V3 SimpleModule same as TinkerGraph. I have written a V2
SimpleModule but how in IoEdgeTest will the correct IoRegistry or
SimpleModule be selected? The test itself does not call addCustomModule()
and between the builders, mappers, registries and modules I don't see how
to add it.

Thanks,
Pieter

On 05/09/2017 16:30, Stephen Mallette wrote:

You have registries for each version as well and default to v3. Please see
TinkerGraph:

https://github.com/apache/tinkerpop/blob/master/tinkergraph-
gremlin/src/main/java/org/apache/tinkerpop/gremlin/
tinkergraph/structure/TinkerGraph.java#L198

If the user wants to override that then that's their choice, but they have
to rig it all up. We probably need a better system than this. IO is way
too
complicated and confusing.

On Tue, Sep 5, 2017 at 9:52 AM, pieter gmail <pieter.mar...@gmail.com>
wrote:

Afraid I still don't quite get it. How do I register the different
SimpleModules depending on the version.

Currently it starts in SqlgGraph,

@Override
public <I extends Io> I io(final Io.Builder<I> builder) {
      return (I) builder.graph(this).onMapper(mapper ->
mapper.addRegistry(SqlgIoRegistry.getInstance())).create();
}

and the SqlgIoRegistry registers the SimpleModule

private SqlgIoRegistry() {
      final SqlgSimpleModule sqlgSimpleModule = new SqlgSimpleModule();
      register(GraphSONIo.class, null, sqlgSimpleModule);
      register(GryoIo.class, RecordId.class, null);
}


Is the SqlgGraph.io(...) method suppose to interrogate the builder to
check the version and add a corresponding IoRegistry and SimpleModule?

Thanks
Pieter






On 05/09/2017 13:30, Stephen Mallette wrote:

I think you should just create a new SimpleModule for each version -
don't
try to put them in the same SqlgSimpleModule. It's a naming convention
that
users will have to follow rather than something explicitly enforced
through
code.

On Sun, Sep 3, 2017 at 3:20 PM, pieter gmail <pieter.mar...@gmail.com>
wrote:

Hi,

I am getting IO tests failures on 3.3.0.

Sqlg has a SimpleModule which add serializers for its custom id.

       SqlgSimpleModule() {
           super("custom");
//        addSerializer(RecordId.class, new
RecordId.RecordIdJacksonSerial
izerV2d0());
//        addDeserializer(RecordId.class, new
RecordId.RecordIdJacksonDeserializerV2d0());
//        addSerializer(SchemaTable.class, new
SchemaTable.SchemaTableIdJacksonSerializerV2d0());
//        addDeserializer(SchemaTable.class, new
SchemaTable.SchemaTableIdJacksonDeserializerV2d0());

           addSerializer(RecordId.class, new
RecordId.RecordIdJacksonSerial
izerV3d0());
           addDeserializer(RecordId.class, new
RecordId.RecordIdJacksonDeseri
alizerV3d0());
           addSerializer(SchemaTable.class, new
SchemaTable.SchemaTableJacksonSerializerV3d0());
           addDeserializer(SchemaTable.class, new
SchemaTable.SchemaTableJacksonDeserializerV3d0());
       }

How is it suppose to distinguish between v2 and v3?

An example of a failure is 'IoEdgeTest.shouldReadWriteEdge'

If ...V2d0.. is added to the serializers then 'graphson-v3' fails.
If ...V3d0.. is added to the serializers then 'graphson-v2' fails.

TinkerPop's own CustomId tests do not rely on default behavior and
manually creates SimpleModules for each scenario.

Are they both suppose to work somehow?

Thanks
Pieter




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