On Monday, 4 January 2021 at 14:40:31 UTC, ag0aep6g wrote:
On 04.01.21 15:37, Ola Fosheim Grøstad wrote:
On Monday, 4 January 2021 at 14:11:28 UTC, ag0aep6g wrote:
`Bar!int` is an alias. It's indistinguishable from `Foo!int`.
The code fails in the same manner when you replace "Bar!int"
with "Foo!int".
Wrong. This succeeds:
struct Foo(T) {}
alias Bar(T) = Foo!T;
void f(T)(Foo!T x) {}
void main() {
f(Bar!int());
}
You didn't replace "Bar!int" with "Foo!int". You replaced
"Bar!T" with "Foo!T". That's something else entirely.
IMO, this is a better example, even if it's a little more verbose.
struct Foo(T) {}
alias Bar(T) = Foo!T;
void f(T)(Bar!T x) {}
void main() {
auto x = Bar!int();
f(x);
}