On Monday, 4 January 2021 at 14:11:28 UTC, ag0aep6g wrote:
`Bar!int` is an alias. It's indistinguishable from `Foo!int`. The code fails in the same manner when you replace "Bar!int" with "Foo!int".


Wrong. This succeeds:

 struct Foo(T) {}

  alias Bar(T) = Foo!T;

  void f(T)(Foo!T x) {}

  void main() {
    f(Bar!int());
  }


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