Re: Should out/ref parameters require the caller to specify out/ref like in C#?

[Dukc via Digitalmars-d]

On Monday, 29 May 2017 at 07:46:07 UTC, Stanislav Blinov wrote:
On Monday, 29 May 2017 at 07:39:40 UTC, Dukc wrote:
[snip]

Explicitly? It is:

import std.stdio;

struct S
{
    int v;
}

void foo(ref S s)
{
    writeln("took S by ref: ", s.v);
}

void foo(S s)
{
    writeln("took rvalue S...");
    foo(s);      // calls ref overload
}

void main()
{
    S s;
    foo(s);      // calls ref overload
    foo(S.init); // calls rvalue overload
}

And for templates we have auto ref.

Of course, I should have noticed one can already do it that way. 
No need for change, then (imo).