KennyTM~ wrote:
On Nov 28, 09 22:00, bearophile wrote:
Walter Bright:
and then s.foo(3), if foo is not a compile time member of s, is
rewritten as:
s.opDynamic!("foo")(3);
I don't understand, isn't this the right translation?
s.opDynamic("foo", 3);
If the "foo" name is known at compile time only (as in all C# examples
and in Python) you can't use a template argument.
(And then it becomes useful to have associative arrays that are fast
when the number of keys is small,< 10).
Bye,
bearophile
Probably because you can write
Variant myOpReallyDynamic(string name, Variant[] s...) {
...
}
Variant opDynamic(string name)(Variant[] s...) {
return myOpReallyDynamic(name, s);
}
but not the other way round.
That is correct. Thanks for pointing that out. The operator is dynamic
because it may perform a dynamic lookup under a static syntax. Straight
dynamic invocation with a regular function has and needs no sugar.
Andrei
