Are you sure the user has been marked as is_staff or is_superuser? http://docs.djangoproject.com/en/dev/topics/auth/#django.contrib.auth.models.User.is_staff
On Wed, Nov 17, 2010 at 18:26, bingbang <thebiggestbangthe...@gmail.com> wrote: > Dear all, > Started learning Django 3 days ago. Great tutorials. Just > made a modified version of the poll app. I am now facing a small > problem, given my newbie-ishness with Python, its proving to be a > little hard to solve for me. I searched this group and did find some > similar issues reported, I tried out the suggestions but there is > probably something I am missing here. Any suggestions will be > great :-) . > > Problem: Can't login as a normal user via the standard http://127.0.0.1/admin/ > page. > Can log in as admin, have created user account, have modified > permission, user account is active but still I get :Please enter a > correct username and passwd" > > I have entered user accounts via the shell and the web interface.. > neither user accounts work. Point to note is that in my urls.py I have > not set up a view for users, I have also not written any login() code > for users, I assumed that a user can login via the admin interface. Is > this valid. > > I did read the /en/dev/faq/admin/ pages but it did not help a lot. > > Any suggestions are very appreciated. > > Thanks! > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.