Try changing this fragment: for q in y: styles = Choice.objects.get(id=q.id).style_set.all()
to something like this: choice_ids = [c.id for c in y] styles = Style.objects.filter(choice__id__in=choice_ids).distinct() If that works, you shouldn't need a set or a map to weed out duplicates. Incidentally, set() doesn't do the trick for you because you get two different instances of the Style model class. Granted that they both represent the same row of data in your DB but they are still two different Python object instances unless you add comparison methods in your Style class that make it seem to Python that they are the same object. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
