On Sun, 2006-05-28 at 19:57 +0200, Roland Scheidegger wrote:
> Rune Petersen wrote:
> 
> >> (e.g.  while (ret && (errno == EINTR || errno == EBUSY));)
> >> And by looking at it, does it make sense that the timeout value in the 
> >> kernel depends on the kernel-of-the-day HZ value, rather than some 
> >> hardware-dependant (probably fixed) value?
> > 
> > Isn't the timeout value dependent on HZ?
> > 3*HZ is always 3 seconds no matter what HZ is (provided its the same 
> > value used to compile the kernel).
> Ah right. I think I misinterpreted something. That said, 3 seconds 
> sounds like a rather long time, why would there still be timeouts?

Because lockups do happen. I think these timeouts are one kind of common
symptoms of a lockup.


-- 
Earthling Michel Dänzer           |          http://tungstengraphics.com
Libre software enthusiast         |          Debian, X and DRI developer




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