At 12:13 PM +0200 9/21/03, Kevin Venzke wrote:
But in most Participation failure examples
I've seen, the same candidate is not the winner in both sets.  For example,
for MCA:

5 A>B>C
4 B>C>A

add in: 2 C>A>B

The winner of the two sets of votes are A and C. Combined, the winner is B.

What method did you use to determine that:


  5:A>B>C
  4:B>C>A
  2:C>A>B

was B?

Whether you add in those last two votes are not, I compute the winner to be A under RP(wv) (http://www.ericgorr.net/condorcet/).


-- == Eric Gorr ========= http://www.ericgorr.net ========= ICQ:9293199 === "Therefore the considerations of the intelligent always include both benefit and harm." - Sun Tzu == Insults, like violence, are the last refuge of the incompetent... === ---- Election-methods mailing list - see http://electorama.com/em for list info

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