On Sun, 21 Sep 2003, Eric Gorr wrote:
^^^^^^^At 12:13 PM +0200 9/21/03, Kevin Venzke wrote: >But in most Participation failure examples >I've seen, the same candidate is not the winner in both sets. For example, >for MCA:
What method did you use to determine that:
5:A>B>C 4:B>C>A 2:C>A>B
was B?
Majority Choice Approval by the looks of it.
Yes...spotted it right after I send the message. Looks like it's time to apply standard excuse #12353...temporary blindness.
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