> -----Original Message----- > From: James Green-Armytage > Commentary: > I think that Paul is right about the number of possible > arrangements > given 100 children and 4 classes, which means that I am most > likely wrong. > My second guess at the magic number is (100!)/((25!)^4)... is that > correct, Paul? I obviously need to brush up on my probability and > statistics. Any idea what is the order of magnitude for > (100!)/((25!)^4)?
The order of magnitude of (100!)/((25!)^4) is ~ 1.61 x 10^57, same as what I got from the C(100,25) x C(75,25) x C(50,25) x 1 analysis. ---- Election-methods mailing list - see http://electorama.com/em for list info
