PS. I've decided to call it the Saari Octahedron from now on, seeing as
though it really isn't cubic or even rhomboid.
On Wed, 8 Dec 1999, Markus Schulze wrote:
> Dear Craig,
>
> it seems to me that you walked into Saari's trap.
>
> Although you don't promote the Borda Method, you
> use Saari's geometrical model of elections. But
> Saari's geometrical model of elections implicitely
> presumes that there is an even distribution of
> candidates. Otherwise it wouldn't be possible that
> the Saari cube is spanned only by the candidates
> (and not e.g. also by the voters). But if there is
> an even distribution of candidates, then the Borda
> Method is _obviously_ the unique best possible
> method.
>
> Although you don't yet promote the Borda Method,
> you check every proposed criterion for compatibility
> with Saari's model and you accept a criterion only
> if it is compatible with Saari's model and you
> reject a criterion if it is incompatible with
> Saari's model. If you keep using Saari's model, then
> in the long run you will necessarily get to the
> conclusion that the Borda Method is the unique best
> possible method.
>
> Markus Schulze
>
>
>
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Nothing is foolproof given a talented fool.