On Tue, 2007-11-27 at 13:28 -0800, Kirk Wallace wrote: > I believe you don't need the J. All you need are two points on the > circle and a line known to contain the center. Take the two points and > draw a line through them. Draw a perpendicular line through the > midpoint. Where your I line intersects the perpendicular line is your > radius center. Now that you mention it, I have have called out both I > and J in my programs which I guess is erroneous. I suppose G2/3 uses the > first option it sees and ignores the rest?
No, it uses both if supplied, and then checks to make sure start_rad=end_rad and that rad!=0. If either of the two offsets (relevant to the currently selected plane) is not supplied, it is assumed to be zero. Your method on the other hand would (I think) always define a valid arc! Nice idea! I don't know how to put it into practice such that it would fit with the present scheme of doing things, but it's something to think about. Thanks, Matt ------------------------------------------------------------------------- SF.Net email is sponsored by: The Future of Linux Business White Paper from Novell. From the desktop to the data center, Linux is going mainstream. Let it simplify your IT future. http://altfarm.mediaplex.com/ad/ck/8857-50307-18918-4 _______________________________________________ Emc-users mailing list Emc-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/emc-users
