Exactly!
One way to do this is to give methods an implicit parameter "here" (the object
in which a method was found during dispatch), in addition to "this".
Then
super.foo(x, y)
would desugar to
Object.getPrototypeOf(here).foo.call(this, x, y)
With call() and apply(), you would have here === this.
Axel
On Jun 19, 2011, at 19:44 , Peter Michaux wrote:
> On Sun, Jun 19, 2011 at 10:20 AM, Axel Rauschmayer <a...@rauschma.de> wrote:
>> It would be nice if "super" could work in any method and not just those
>> methods that are defined inside an object literal. Then, a method would have
>> to know what object it resides in, e.g. via an implicit parameter.
>
> So you want "super" to be dynamic but tied to the value of "this"
> inside that function? Something like...
>
> function fn() {
> return this.alpha + super.beta();
> }
>
> function Foo() {}
> Foo.prototype.alpha = function() {return 1;};
> Foo.prototype.beta = function() {return 2;};
>
> function Bar() {}
> Bar.prototype = Object.create(Foo.prototype);
> Bar.prototype.beta = function() {return 5;};
>
> var b = new Bar();
> fn.call(b); // 1 + 2 = 3
>
> Peter
>
--
Dr. Axel Rauschmayer
a...@rauschma.de
twitter.com/rauschma
home: rauschma.de
blog: 2ality.com
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