Hi John,

One might think it was the acceleration that slowed time on A's clock, BUT 
the point is that A's acceleration was only 1g throughout the entire trip 
which was exactly EQUAL to B's gravitational acceleration back on earth. So 
if the accelerations were exactly equal during the entire trip how could 
A's acceleration slow time but B's not slow time by the same amount?

Edgar



On Friday, January 31, 2014 1:59:59 PM UTC-5, John Clark wrote:
>
>
>
>
> On Thu, Jan 30, 2014 at 4:36 PM, Edgar L. Owen <edga...@att.net<javascript:>
> > wrote:
>
> > A is traveling at near light speed most of the trip. That's why B sees 
>> A's clock slow 
>>
>
> Yes. And from A's point of view he's standing still and B is traveling at 
> near light speed, so A sees B's clock running slow. Both would see the 
> others clock as running slow.  However if A decided to join B so they could 
> shake hands and directly compare the times their clocks show then A is 
> going to have to accelerate, and then things would no longer be 
> symmetrical, then A would see B's clock running FAST but B would still see 
> A's clock run SLOW. So when they joined up again and compared clocks they 
> would not match, B's clock would be ahead and B would have aged more than A.
>
> > So my question is this: Why does A's clock slowing turn out to be ACTUAL 
>> (agreed by both A and B) when he stops at the center of the galaxy, and B's 
>> slow clock slowing doesn't? 
>>
>
> Because A stopped, and that means A must have accelerated but B did not.
>
>   John K Clark
>
>
>

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