On Wed, Mar 5, 2014 at 2:52 PM, Edgar L. Owen <edgaro...@att.net> wrote:

> Jesse,
>
> Yes, the views are infinite on several axes, but that can be addressed
> simply by enumerating views at standard intervals on those axes.
>

But velocity intervals which are equal when the velocities are defined
relative to one frame are not equal when the velocities are defined
relative to a different frame. I already mentioned an example where if a
frame 1 has velocity v=0.1c relative to me and another frame 2 has velocity
v=0.15c relative to me, then the interval between them is 0.05c from my
perspective, and likewise if a frame 3 has velocity v=0.9c relative to me
and another frame 4 has velocity v=0.95c relative to me, then they have the
same interval of 0.05c from my perspective; but for another observer moving
at v=0.8c relative to me, frame 1 has a velocity of -0.761c and frame 2 has
a velocity of -0.739c (so the interval between 1 and 2 is 0.022 for this
observer), whereas frame 3 has a velocity of 0.357c and frame 4 has a
velocity of 0.625c (so the interval between 3 and 4 is 0.268c for this
observer, more than ten times larger than the interval between 1 and 2).
These velocities are calculated using the relativistic velocity formula at
http://math.ucr.edu/home/baez/physics/Relativity/SR/velocity.html where u =
-0.8c is my velocity relative to the second observer, and v is the velocity
of any given frame 1,2,3, or 4 relative to me.

Point is, if your "intervals" are equal relative to one frame but unequal
relative to all other frames, then you are privileging a particular frame's
perspective from the start.



> Or you could equally integrate over the continuous functions.
>

As I said, the only way to do this is to use some sort of weight/measure
function, and a weight/measure function which is uniform when plotted
against velocity in one frame will be non-uniform when plotted against
velocity in other frames, so there doesn't seem to be a way of picking such
a function that doesn't privilege one frame from the start.



>
> Considered together simply means you plot the correlation each frame view
> (at the standard intervals as above) gives and see how they cluster. Which
> I'm pretty sure will be around my result.
>

The will "cluster" around the judgment of whatever frame you choose to
privilege from the start, either by your definition of "equal intervals" or
by your weighting/measure function. So, using this to conclude anything
about the "actual" correlation would just be another piece of circular
reasoning.

Jesse




>
> You don't need to view the resulting graph from any frame as you seem to
> suggest, because the graph is OF the actual all frame view results.
>
> For every frame you simply calculate the apparent lack of simultaneity
> between two events Nonsiimultaneity=(t1-t2) and plot it relative to the
> simultaneity that my method claims is actual.
>
> Edgar
>
>
>
> On Wednesday, March 5, 2014 2:13:24 PM UTC-5, jessem wrote:
>>
>>
>>
>> On Wed, Mar 5, 2014 at 1:27 PM, Edgar L. Owen <edga...@att.net> wrote:
>>
>> Jesse,
>>
>> Yes, you are right. I phrased it incorrectly.
>>
>> What I meant to say was not that each individual view was somehow
>> weighted, but that all views considered together would tend to cluster
>> around m
>>
>> ...
>
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