On 04 Jul 2014, at 02:15, Stephen Paul King wrote:

Hi Bruno,

  Is the measure idempotent?


How could a measure function be idempotent? It is a function from some algebra of sets into some order or number structure. You cannot apply the measure a second times on its result, as it will not have the right type.

Well, with enough imagination, I can object to myself, by "confusing" the measure result, and the measure tool. If you measure the hight of man with a meter, and find 1m80, then if you remeasure the meter itself up to the 1m80 point, you will find the same result, and may be you meant only the following question:

Is it true that in comp, if we make quickly a measurement two times we will find the same results. That is an open question of course, but thanks to the p -> []<>p, we have what is needed to expect that this is possible. With some chance we might get the quantum Zeno freezing effect (discovered by Turing): if we look seriously very often to a particle state, we project it on the same state, and it freezes.

Bruno





On Thu, Jul 3, 2014 at 1:14 PM, Bruno Marchal <marc...@ulb.ac.be> wrote:

On 03 Jul 2014, at 06:51, Richard Ruquist wrote:

Quantum measure is the result of solving Schrodinger's Eq.
yielding a different probability for each quantum state
 and a different measure for each different scenario
unlike the invariant measure of the reals.
Do you disagree?
Richard


The quantum measure is a measure on solutions of an equation, like square normed functions or operators in a linear (Hilbert) space (like in both QM and functional analysis). The measure on the reals is a measure on real numbers. With comp, the measure is on the relative states. It is really a measure on the transition <a I b>. In quantum mechanics it is given by [<a I b>]^2, but with comp this must be explained by a measure on all the computations going from a mind state corresponding to observing 'a to a mind state of observing 'b, taking into account the fact that an infinity of universal numbers justifies those transitions (= makes them belonging to a computation).

The protocol of the iterated WM-duplication is a very particular case. The first person histories with computable sequence like "WWWWWW...", or "WMWMWMWMWM... ", becomes the white rabbits event, and the norm is high incompressibility (a very strong form of randomness).

The ultimate protocol is the "logical" structure of the sigma_1 arithmetic. By the dovetailing on the reals, it mixes a random oracle with the halting oracle so that we can expect a "non-machine" for the first person truth. But it is already a non machine, from the machine view, by simple incompleteness.

The interview of the löbian machine does not provide the measure calculus (Plato-Plotinus 'bastard' calculus with the Plotinus lexicon), but it provides the logic of the measure one, from which the measure calculus + the arithmetical constraints) should be derivable (and the measure one admits a quantization confirming things go well there).

Bruno



On Thu, Jul 3, 2014 at 12:44 AM, Russell Standish <li...@hpcoders.com.au > wrote:
On Thu, Jul 03, 2014 at 12:23:35AM -0400, Richard Ruquist wrote:
> On Wed, Jul 2, 2014 at 10:34 PM, Russell Standish <li...@hpcoders.com.au >
> wrote:
>
> > On Tue, Jul 01, 2014 at 04:30:52PM -0400, Stephen Paul King wrote:
> > > Hi Russell,
> > >
> > > Ah! I don't quite grok it completely, but thank you for this example. We > > > had to assume an already existing measure on the Reals. Where does that
> > > come from?
> > >
> >
> > The standard measure on the reals is based on the observation that we > > expect the set of real numbers starting with 0.110... to have the same > > measure as those starting with 0.111... That would be a reasonable
> > default assumption for most purposes.
>
>
> The measure obtained by compression of the reals in binary form is close to
> the quantum mechanic measure, but not exact.
> In fact, the quantum measure varies with the scenario, whereas the measure
> of the reals is invariant.
> Richard
>

What do you mean? What is this "quantum measure"?

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