On 25 Jun 2015, at 04:15, spudboy100 via Everything List wrote:
But what of pancomputationalism?
On what "pan" is applied?
If "pan" is large and contains whatever is not me, then that is
provably non computational. If "I am a machine" (exactly: if my 3-self
is Turing emulable) then Not-Me is not a machine.
Only a tiny part of the arithmetical truth is Turing emulable. Most
machine's property are not Turing emulable. I showed this for the
predicate "being the code of a total computable function": this is not
computably solvable.
Is the physical reality pancomputable. Normally no. Its computable
aspect might be a problem for comp, except that physics does contain
non computable aspects too, of the same kind as the FPI (the wave
collapse, for example). So even the physical is plausibly not entirely
computable, but this can be approximated in comp by lowering the
substitution level enough.
Bruno
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-----Original Message-----
From: John Clark <johnkcl...@gmail.com>
To: everything-list <everything-list@googlegroups.com>
Sent: Wed, Jun 24, 2015 08:57 PM
Subject: Re: A riddle for John Clark
On Wed, Jun 24, 2015 Quentin Anciaux <allco...@gmail.com> wrote:
> neither will contain "I see Moscow and I see Washington"
Yes, and because John Clark HAS BEEN DUPLICATED and there are
now two John Clarks it would not be expected that just one interview
would settle the question of what cities John Clark saw. The first
interviewee says "I am John Clark and I see Moscow". The second
interviewee says "I am John Clark and I see Washington".
So Quentin, from the above information even a man with a room
temperature IQ such as yourself should be able to answer the
question " what cities did John Clark see?".
> If you could quit the list with your horses that would be
really cool
You make it clear that if I quit the list it would make you very
happy, therefore I will not quite the list. You're a lousy
psychologist, you should have said you'd cry like a baby if I quit
the list.
John K Clark
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