On 04-10-2019 09:10, Bruce Kellett wrote:
On Fri, Oct 4, 2019 at 5:03 PM smitra <smi...@zonnet.nl> wrote:
The descendant worlds get the same energy if they have well defined
energy in which case computing the weighted average to get to the
expectation value is unnecessary. In general the expectation value
will
need to be computed by this weighted average. To see that this is
not
crazy, suppose that QM is not the ultimate answer that 't Hooft is
correct. But it then turns out that 't Hooft's deterministic models
lead
to a multiverse via the back door due to Poincare recurrence. And
because with finite information in our brains, we cannot locate
ourselves in a particular time period. Then when we do an
experiment, a
splitting can occur in the sense that we now get more precisely
located
across in the different sectors separated by astronomical large
amounts
of time. So, no problem here with the sum of the energy of
(effective)
branches increasing.
Where is all this in the Schrodinger equation?
We should start with listing all possibilities:
1) Schrodinger equation is exactly correct, in which case we have to
accept the MWI.
2) Schrodinger equation is only an approximation.
Under option 2) we can have single world theories where a real collapse
happens that violates the Schrodinger equation. But it's also possible
that the violation of the Schrodinger equation leading to a collapse
doesn't actually get rid of the Many Worlds part of the MWI. The way the
collapse happens will be different for the copies of an observer that
will exist in a large enough universe (in a spatial or temporal sense).
Saibal
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