On 06-10-2019 12:38, Bruce Kellett wrote:
On Sun, Oct 6, 2019 at 8:37 PM smitra <smi...@zonnet.nl> wrote:
On 04-10-2019 09:10, Bruce Kellett wrote:
On Fri, Oct 4, 2019 at 5:03 PM smitra <smi...@zonnet.nl> wrote:
The descendant worlds get the same energy if they have well
defined
energy in which case computing the weighted average to get to the
expectation value is unnecessary. In general the expectation
value
will
need to be computed by this weighted average. To see that this is
not
crazy, suppose that QM is not the ultimate answer that 't Hooft
is
correct. But it then turns out that 't Hooft's deterministic
models
lead
to a multiverse via the back door due to Poincare recurrence. And
because with finite information in our brains, we cannot locate
ourselves in a particular time period. Then when we do an
experiment, a
splitting can occur in the sense that we now get more precisely
located
across in the different sectors separated by astronomical large
amounts
of time. So, no problem here with the sum of the energy of
(effective)
branches increasing.
Where is all this in the Schrodinger equation?
We should start with listing all possibilities:
1) Schrodinger equation is exactly correct, in which case we have to
accept the MWI.
False.
You can try to invoke Bohm theory as a counterexample, but as David
Deutsch has demonstrated, Bohm theory is just the MWI in disguise.
Saibal
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