On Sun, Oct 6, 2019 at 8:37 PM smitra <smi...@zonnet.nl> wrote:

> On 04-10-2019 09:10, Bruce Kellett wrote:
> > On Fri, Oct 4, 2019 at 5:03 PM smitra <smi...@zonnet.nl> wrote:
> >
> >> The descendant worlds get the same energy if they have well defined
> >> energy in which case computing the weighted average to get to the
> >> expectation value is unnecessary. In general the expectation value
> >> will
> >> need to be computed by this weighted average. To see that this is
> >> not
> >> crazy, suppose that QM is not the ultimate answer that 't Hooft is
> >> correct. But it then turns out that 't Hooft's deterministic models
> >> lead
> >> to a multiverse via the back door due to Poincare recurrence. And
> >> because with finite information in our brains, we cannot locate
> >> ourselves in a particular time period. Then when we do an
> >> experiment, a
> >> splitting can occur in the sense that we now get more precisely
> >> located
> >> across in the different sectors separated by astronomical large
> >> amounts
> >> of time. So, no problem here with the sum of the energy of
> >> (effective)
> >> branches increasing.
> >
> > Where is all this in the Schrodinger equation?
>
> We should start with listing all possibilities:
>
> 1) Schrodinger equation is exactly correct, in which case we have to
> accept the MWI.
>

False.


> 2) Schrodinger equation is only an approximation.
>

Possible, but irrelevant here. This does not go towards answering the
question that was asked about energy.

Bruce


Under option 2) we can have single world theories where a real collapse
> happens that violates the Schrodinger equation. But it's also possible
> that the violation of the Schrodinger equation leading to a collapse
> doesn't actually get rid of the Many Worlds part of the MWI. The way the
> collapse happens will be different for the copies of an observer that
> will exist in a large enough universe (in a spatial or temporal sense).
>
> Saibal
>

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