On Sunday, October 20, 2019 at 6:35:10 PM UTC-6, Brent wrote:
>
>
>
> On 10/20/2019 4:58 PM, Alan Grayson wrote:
>
> On Sunday, October 20, 2019 at 11:35:13 AM UTC-6, Brent wrote: 
>>
>>
>>
>> On 10/19/2019 6:56 PM, Alan Grayson wrote:
>>
>> Sean says the decoherence time is 10^(-20) sec. So when the box is 
>>> closed, the cat is in a superposition of alive and dead during that time 
>>> interval, assuming the decay hasn't happened. If that's the case, I don't 
>>> see how decoherence solves the paradox, unless we can assume an initial 
>>> condition where the probability of one component of the superposition, that 
>>> the cat is dead, is zero. Maybe this is the solution. What do you think? AG
>>>
>>
>> Maybe this is an easier question; after decoherence, assuming the 
>> radioactive source hasn't decayed, what is the wf of the cat?  Is the cat 
>> in a mixed state, alive or dead with some probabIlity for each? AG
>>
>>
>> You can't "assume the radioactive source hasn't decayed".  The point 
>> Schroedinger's thought experiment is that when the box is closed you don't 
>> know whether or not it has decayed and so it is in a superposition of 
>> decayed and not-decayed and the cat is correlated with these states, so it 
>> is also in a superposition of dead and alive.
>>
>> Brent
>>
>
> I thought you might say this. OK, then what function does decoherence have 
> in possibly solving the apparent paradox of a cat alive and dead 
> simultaneously. TIA, AG 
>
>
> It doesn't necessarily solve "that problem".  Rather it shows why you can 
> never detect such a state, assuming you buy Zurek's idea of envariance.  
> One way to look at it is it's the answer to Heisenberg's question: Where is 
> the cut between the quantum and the classical?  Once envriance has acted, 
> then the result is classical, i.e. you can ignore the other possibilities 
> and renormalize the wave function.
>
> Brent
>

Woudn't you agree that if the system, in the case a cat, goes classical 
after 10^(-20) sec, its state must be a mixture at that point in time even 
if the box hasn't been opened?  AG 

-- 
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to everything-list+unsubscr...@googlegroups.com.
To view this discussion on the web visit 
https://groups.google.com/d/msgid/everything-list/43aedf54-a007-42b3-aab5-c4ef02f72c3f%40googlegroups.com.

Reply via email to