Actually, here's how you can do this in Factor using the with-datastack word:
USING: kernel math prettyprint sequences ;
{ 1337 } [ [ dup 1 > ] [ 2/ dup ] while ] with-datastack
It's clean looking, but it's pretty slow.
Doug
On Tue, Jun 19, 2012 at 8:33 PM, Doug Coleman <doug.cole...@gmail.com> wrote:
> How would you do this in C? Would you take the return address off the
> stack frame, then start calculating the division-by-2s and pushing
> them to the local stack frame in a loop, and then walk back up
> accumulating them in an array until you hit the return address, at
> which point you return the array?
>
> That's kind of what it sounds like you're suggesting, which would be
> kind of fun but totally impractical. In C, you'd collect them
> immediately after you calculate them, too, just like you should in
> Factor.
>
> The data stack is not for storing all your data, just for threading
> arguments and return values between word calls in a predictable way
> (known stack height.)
>
> Is that helpful? :)
>
> Doug
>
> On Tue, Jun 19, 2012 at 8:26 PM, Graham Telfer <gakouse...@hotmail.com> wrote:
>> Marshall Lochbaum <mwlochbaum@...> writes:
>>
>>>
>>>
>>> I figured there would be a word designed for that already... Here's my take
>>> on
>> this anyway.
>>> I would append the items to a sequence as the algorithm goes along:
>>> { } swap [ dup 1 > ] [ dup 2 /i [ suffix ] dip ] while suffixaccomplishes
>>> the
>> task.
>>>
>>> Marshall
>>
>> Hi Marshall,
>>
>> Yes, this works but I feel the two tasks are conceptually different and I
>> didn't
>> want to interleave them. I wanted to do all the division as 1 job and then
>> just
>> push the results as the 2nd job. This way the code stays simple and properly
>> factored.
>>
>> Graham
>>
>>
>>
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