As long as you can fully round-trip the integer, it doesn't matter how many
bytes you use.

nano-count dup 4 >be be> = .
f

nano-count dup 8 >be be> = .
t

nano-count dup 128 >be be> = .
t


``log2 1 +`` will give you the required number of bits to store an integer.
You will want to round up to a power of 8 bits or a power of two bytes.

USE: math.bitwise
nano-count dup dup log2 1 + bits =

On Fri, Jun 5, 2020 at 4:44 PM Alexander Ilin <ajs...@yandex.ru> wrote:

> Hello again!
>
>  My specific example is the following. I want to put the output of
> `nano-count` into a `byte-array`, which is fed into a hash. The current
> value of `nano-count` is one of the sources of randomness gathered from the
> system and poured into the hash. To convert the integer value into a
> `byte-array` there are `>le` and `>be`, but they require the number of
> bytes as a parameter. The question is, what should I supply for the value
> received from `nano-count`?
>
>  And the bigger question is, given an integer value, is there a way to
> interrogate it about its byte size, i.e. the minimum number of bytes it
> takes to hold the value without truncation and without leading zeroes:
>
>  Value -- MinSize
>  0 -- 1
>  255 -- 1
>  256 -- 2
>  65535 -- 2
>  65536 -- 3
>  etc.
>
>  I would expect such information to be available somewhere without doing
> the power of two calculations in a loop.
>
> 23.03.2020, 05:41, "Doug Coleman" <doug.cole...@gmail.com>:
>
> For Factor, integers are either fixnum or bignum size. For C, you tell it
> how many bytes it occupies according to the C header. Generally the sizes
> are the same across platforms. If they aren't, you might need two different
> STRUCT: declarations like in basis/unix/stat/linux/32/32.factor
> and basis/unix/stat/linux/64/64.factor.
>
> The main point -- function signatures and struct declarations usually
> handle the integer sizes and you shouldn't have to think much about it. Do
> you have a specific example?
>
>
>
>
> Earlier I wrote:
>
>  One more question. I want to convert an integer into a byte-array
> containing its bytes. In my use case it was the return value of the
> nano-count, but the question is general: how can I get the bytes of an
> integer.
>
>  For floats there are primitives like float>bits and double>bits, and for
> integers there is >le and >be, but for the latter two I need to specify the
> size in bytes. Is there a way to ask an integer how many bytes it occupies?
> Because from the documentation it's not clear at all how many bytes
> nano-count would return, and it may vary depending on the current platform.
> What am I missing?
>
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