Yes, you can see this using ripgrep:
➜ factor-master git:(master) ✗ cd vm
➜ vm git:(master) ✗ rg nano_count
os-genunix.cpp
30:uint64_t nano_count() {
os-windows.hpp <-----------------------
70:uint64_t nano_count();
os-macosx.mm
77:uint64_t nano_count() {
vm.cpp
31: last_nano_count(0),
os-unix.hpp
49:uint64_t nano_count();
os-windows.cpp <------------------------
147:uint64_t nano_count() {
155: // nano_count calls would show a difference of about 1 second,
factor.cpp
67: srand((unsigned int)nano_count());
gc.cpp
10: start_time(nano_count()),
14: start_time = nano_count();
17:void gc_event::reset_timer() { temp_time = nano_count(); }
20: times[phase] = (cell)(nano_count() - temp_time);
26: total_time = (cell)(nano_count() - start_time);
32: start_time = nano_count();
run.cpp
12:void factor_vm::primitive_nano_count() {
13: uint64_t nanos = nano_count();
14: if (nanos < last_nano_count) {
16: std::cout << std::hex << last_nano_count;
21: last_nano_count = nanos;
primitives.hpp
32: _(minor_gc) _(modify_code_heap) _(nano_count) _(quotation_code)
\
vm.hpp
140: uint64_t last_nano_count;
176: void primitive_nano_count();
On Fri, Jun 5, 2020 at 5:14 PM Alexander Ilin <ajs...@yandex.ru> wrote:
> Does it also return 8 bytes in 32-bit Windows?
>
> 06.06.2020, 01:09, "Doug Coleman" <doug.cole...@gmail.com>:
>
> Actually, I can be more helpful. ``nano-count`` returns a ``uint64_t`` so
> you need 8 bytes.
>
> In vm/os-genunix.cpp:
>
> uint64_t nano_count() {
> struct timespec t;
> int ret = clock_gettime(CLOCK_MONOTONIC, &t);
> if (ret != 0)
> fatal_error("clock_gettime failed", 0);
> return (uint64_t)t.tv_sec * 1000000000 + t.tv_nsec;
> }
>
> On Fri, Jun 5, 2020 at 5:00 PM Doug Coleman <doug.cole...@gmail.com>
> wrote:
>
> As long as you can fully round-trip the integer, it doesn't matter how
> many bytes you use.
>
> nano-count dup 4 >be be> = .
> f
>
> nano-count dup 8 >be be> = .
> t
>
> nano-count dup 128 >be be> = .
> t
>
>
>
> ``log2 1 +`` will give you the required number of bits to store an
> integer. You will want to round up to a power of 8 bits or a power of two
> bytes.
>
> USE: math.bitwise
> nano-count dup dup log2 1 + bits =
>
> On Fri, Jun 5, 2020 at 4:44 PM Alexander Ilin <ajs...@yandex.ru> wrote:
>
> Hello again!
>
> My specific example is the following. I want to put the output of
> `nano-count` into a `byte-array`, which is fed into a hash. The current
> value of `nano-count` is one of the sources of randomness gathered from the
> system and poured into the hash. To convert the integer value into a
> `byte-array` there are `>le` and `>be`, but they require the number of
> bytes as a parameter. The question is, what should I supply for the value
> received from `nano-count`?
>
> And the bigger question is, given an integer value, is there a way to
> interrogate it about its byte size, i.e. the minimum number of bytes it
> takes to hold the value without truncation and without leading zeroes:
>
> Value -- MinSize
> 0 -- 1
> 255 -- 1
> 256 -- 2
> 65535 -- 2
> 65536 -- 3
> etc.
>
> I would expect such information to be available somewhere without doing
> the power of two calculations in a loop.
>
> 23.03.2020, 05:41, "Doug Coleman" <doug.cole...@gmail.com>:
>
> For Factor, integers are either fixnum or bignum size. For C, you tell it
> how many bytes it occupies according to the C header. Generally the sizes
> are the same across platforms. If they aren't, you might need two different
> STRUCT: declarations like in basis/unix/stat/linux/32/32.factor
> and basis/unix/stat/linux/64/64.factor.
>
> The main point -- function signatures and struct declarations usually
> handle the integer sizes and you shouldn't have to think much about it. Do
> you have a specific example?
>
>
>
>
> Earlier I wrote:
>
> One more question. I want to convert an integer into a byte-array
> containing its bytes. In my use case it was the return value of the
> nano-count, but the question is general: how can I get the bytes of an
> integer.
>
> For floats there are primitives like float>bits and double>bits, and for
> integers there is >le and >be, but for the latter two I need to specify the
> size in bytes. Is there a way to ask an integer how many bytes it occupies?
> Because from the documentation it's not clear at all how many bytes
> nano-count would return, and it may vary depending on the current platform.
> What am I missing?
>
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