Re: filmscanners: Re: So it's the bits?

[Ray Amos]

Colin Maddock wrote:
> 
> Julian wrote:
> 
> >Because it is an 8-bit D/A, the lowest level we can read is 2^8 lower than
> >1024 = 1024/256 = 4mV.  This is the value of one least significant bit
> >(LSB).   Also, let's assume that this is an optimally engineered 8-bit
> >system. Because it is optimally engineered, let's say that the
> >CCD/amplifier noise is a quarter of the LSB level i.e. 1mV RMS.
> 
> edited here
> >Now, let's unplug the 8 bit D/A, and plug in a 12 bit D/A instead, to the
> >same circuit. My point is - NOTHING CHANGES.
> 
> Won't the 12bit a/d converter allow the information between 4mv and the 1mv noise 
>level to be resolved?
> 
> Colin Maddock

Is there anyone out there other than the participants who has any idea
what they are saying?

Ray Amos