Thanks Steve - have it working. Yep, I love E4X too - still learning all the intricacies like this, so this is another notch in my belt.
(however for anyone listening and for the archives, your code does the opposite of what I want. It removes all nodes WITH children. I want to remove any nodes that DON'T have children. Changing that one line to look for children length greater than 0 does the trick: var list:XMLList = xml..module.(children().length() > 0); ) Thanks for your help, Jason Merrill Bank of America Global Learning Shared Services Solutions Development Monthly meetings on the Adobe Flash platform for rich media experiences - join the Bank of America Flash Platform Community -----Original Message----- From: flashcoders-boun...@chattyfig.figleaf.com [mailto:flashcoders-boun...@chattyfig.figleaf.com] On Behalf Of Steven Sacks Sent: Tuesday, June 09, 2009 12:25 PM To: Flash Coders List Subject: Re: [Flashcoders] XML find and delete nodes Filter the XML using E4X and then make a new XML from that filtered result. var xml:XML = <xml> <modules> <module title="apple"/> <module title="orange"> <node/> </module> <module title="banana"> <node/> </module> <module title="plum"/> <module title="pear"/> <module title="pineapple"> <node/> </module> </modules> </xml>; // var list:XMLList = xml..module.(children().length() == 0); var newXML:XML = <xml/>; xml.setChildren(list); trace(xml); _______________________________________________ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders _______________________________________________ Flashcoders mailing list Flashcoders@chattyfig.figleaf.com http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
