Erik Hofman writes:

 > So now you've got:
 > 
 > 1. friction calculate every wheel separately.
 > 2. add all frictions for the landing gear.
 > 3. make the friction for every wheel dependent to wheel spin and use the 
 > result for moments and force calculations.
 > 4. calculate the moments and forces for the complete landing gear.
 > 
 > 5. calculate the result by averaging(?) the results for the complete 
 > gear (add this for all wheels) and every separate wheel.
 > 
 > Does this make sense?

When standing still, you then have to clamp the forces and moments
somehow so that they don't cause any previous force or moment to
change sign: i.e. the ground reactions can reduce any
previously-cumulated force or moment to zero, but they must not be
allowed to make a positive force or moment negative or vice versa.

When moving, of course, the situation is different, especially in the
z-direction (they call student circuits "bounce-and-go's" for a
reason).


All the best,


David


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