In our previous episode, Mattias Gaertner said: > > > > BTW, > The parser parses expression as whole and only stores the whole > expression as string. This is done because in order to parse an > expression you need to resolve identifiers, because operators are > context sensitive. A simple parser can not do that. If the parser does > not resolve identifiers it can only create symbol structures which > would be as complicated as parsing the expression. > In this sense the fcl parser already supports ^g constants.
I don't fully understand this. Afaik ^ in a constant expression is not related to ^ in a type expression? _______________________________________________ fpc-devel maillist - [email protected] http://lists.freepascal.org/mailman/listinfo/fpc-devel
