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Thanks for your reply, 
However I have now a doubt regarding one aspect that I had not noticed before.

What I wanted to do is to perform the contrast 
(condA>condAcontrol)>(condB>condBcontrol) with the order of my condition being 
condA, condAcontrol, condB, condBcontrol

You said that to do so I should use -a 1 -c 2 -c 3 -a 4, but I don’t understand 
why condition 3 is -c and condition 4 is -a.
To my understanding a is assigning a positive weight to my predictors, while c 
is assigning a negative one.
So if I run  -a 1 -c 2 -c 3 -a 4, am I not testing the contrast 
(condA>condAcontrol)>(condBcontrol>condB) ?

In addition, if now I want to obtain: (condA>condB)>(condAcontrol>condBcontrol) 
should I run mkcontrast-sess -analysis analysis -contrast contrastname -a 1 -c 
3 -c 2 -a 4, or -a 1 -c 3 -a 2 -c 4?


Thanks, 


Paula


> Il giorno 27 ott 2020, alle ore 22:50, Douglas N. Greve 
> <dgr...@mgh.harvard.edu> ha scritto:
> 
> You would just run mkcontrast-sess, eg, if your four conditions are 
> ordered condA, condAcontrol, condB, condBcont, then
> mkcontrast-sess -analysis analysis -contrast contrastname -a 1 -c 2 -c 3 
> -a 4
> If you want it reversed, then just reverse the a's and c's
> 
> On 10/23/2020 4:39 AM, Paula Maldonado wrote:
>>         External Email - Use Caution
>> 
>> Dear experts,
>> I am running an fMRI experiment in which I have four conditions: two main 
>> conditions (condition A and condition B) and two respective control 
>> conditions (condition Acontrol and condition Bcontrol).
>> I would like to create a map showing significantly greater activity for 
>> condition A relative to condition B, after subtracting out the activity for 
>> the respective control conditions. In other words, I would like to perform 
>> the following contrast:
>> (condition A - condition A control) - (condition B - condition B control)
>> Then I would like to have a map that shows the reverse contrast 
>> too:(condition B - condition B control) - (condition A - condition A 
>> control).
>> 
>> How do I do that?To obtain the first map: (condition A - condition A 
>> control) - (condition B - condition B control) I have tried with the 
>> mergecontrasts-sess function with the -conjunction flag and the OR option as 
>> detailed below:
>> mergecontrasts-sess -mergedcontrast conjres -conjunction or -analysis 
>> analysisname -map sig -space sph -isxavg fixed -contrast Contrast1 2 pos 0 
>> -contrast Contrast 2 pos 0 -s sessionsfMRI/Sub01/bold -hemi lh
>> 
>> where Contrast1= (condition A - condition A control) and Contrast2= 
>> (condition B - condition B control)
>> however the map I get is exactly the same as (condition A - condition A 
>> control), as if subtracting out Contrast 2 had no impact on the map.
>> 
>> Thanks,
>> 
>> Paula
>> 
>> 
>> 
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